Home
Class 12
CHEMISTRY
Edge length of M^(+)X (fcc structure) is...

Edge length of `M^(+)X` (fcc structure) is `7.2Å`. Assuming (`M^(+) - X^(-))` contact along the cell edge, radius of `X^(-)` ion is (`r_(M+) = 1.6Å):`

A

2.0 Å

B

5.6 Å

C

2.8 Å

D

3.8 Å

Text Solution

Verified by Experts

The correct Answer is:
A
Edge length (a)` = 2(r_c + r_a)`
`2r_a = a - 2r_c`
Promotional Banner

Topper's Solved these Questions

  • SOLID STATES

    NARAYNA|Exercise EXERCISE-2 (H.W) (TYPES OF SOLIDS)|3 Videos

  • SOLID STATES

    NARAYNA|Exercise EXERCISE-2 (H.W) (CLOSE PACKED STRUCTURES)|4 Videos

  • SOLID STATES

    NARAYNA|Exercise EXERCISE-2 (C.W) (ELECTRICAL MAGNETIC PROPERTIES )|2 Videos

  • QUALITATIVE ANALYSIS

    NARAYNA|Exercise Subjective Type Question|33 Videos

  • SOLUTIONS & COLLIGATIVE PROPERTIES

    NARAYNA|Exercise EXERCISE : 4|26 Videos

Similar Questions

Explore conceptually related problems

Edge length of M^(+)X^(-) (fcc structure) is 7.2^(@)A . Assuming M^(+)-X^(-) contact along the cell edge, radius of X(-) ion is (r_(M+)=1.6^(@)A) :

The unit cube length for LiCl ( NaCl structure) is 5.14 Å . Assuming anion-anion contact, calculate the ionic radius for chloride ion.

The unit cell cube length for LiCl(just like NaCl structures) is 5.14Å . Assuming anion-anion contact, the ionic radius for chloride ion is:

LiCl has rock salt structure, with an edge length of 6.0Å. If anions are in contact, the ionic radius of chloride ion is