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Calculate the electrode potential of giv...

Calculate the electrode potential of given electrode `Pt, Cl_(2) (1.5 "bar") | 2Cl^(-) (0.01 M)`,
Solu `E_(Cl_(2)//2Cl^(-))^(@) = 1.36 V` tion:

Text Solution

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The reaction of electrode is
`{:(Cl_(2)(g) + 2e^(-), to, 2Cl^(-)),(1.5 "bar",,0.01 M):}`
`E = e^(@) -(0.0591)/n log ([Cl^(-)]^(2))/P_(Cl_(2))`
`=1.36 - (0.0591)/2 log (0.01)^(2)/1.5 = 1.483 V`
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