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Find out work done for the given cell ...

Find out work done for the given cell
`Cr|Cr^(+3) || Fe^(+2)| Fe`
`E_(Cr//Cr^(3+))^(@) = 0.74 V, E_(Fe^(2+)//Fe)^(@) = -0.44 V`

Text Solution

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`E_("cell")^(@) = E_("cathode")^(@) - E_("Anode")^(@)`
`=-0.44 V + 0.74 V = 0.30` V
[since cell reaction `2Cr + 3Fe^(2+) to 2Cr^(3+) + 3Fe`, n = 6 mol electron]
`W= -nFE^(@) =-6 xx 96500 xx 0.30 W = 173.7` KJ
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