Find out given cell is spontaneous or non-spontaneous. `H_(2)(P_1)//H^(+) || H^(+) //H_(2)(P_2)`, If `P_(1) gt P_(2)`

Explanation

To determine whether the given electrochemical cell is spontaneous or non-spontaneous, we can follow these steps:

### Step 1: Identify the half-reactions
In the given cell notation `H2(P1)//H+( ) || H+( ) //H2(P2)`, we have:
- **Anode Reaction (Oxidation)**:
\[ H_2(g) \rightarrow 2H^+(aq) + 2e^- \]
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