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How much copper is deposited on the cath...

How much copper is deposited on the cathode if a current of 3A is passed through aqueous `CuSO_(4)` solution for 15 minutes?

Text Solution

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Quantity of electricity passed = Current in amperes x time in seconds.
`Q = 3 xx 15 xx 60 = 2700` C
`Cu^(++) + 2e^(-) to Cu`
Two mole electron or 2F charge can deposit 1.
Mole copper i.e. 63.5 g and so 2700 C will deposit
`=(2700 xx 63.5)/(2 xx 96500) = 0.889` g
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