A solution of `CuSO_(4)` is electroysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode ?
(Molar mass of `Cu=63.5 g//mol)`

Explanation

`Q = I xx t = 1.5 xx 10 xx 60 = 1.6 xx 600 = 900 C`
Reaction occuring at the cathode is
`Cu^(2+) + 2e^(-) to Cu`
`2F = 2 xx 96500` C deposit Cu = 1mole of 63.5 g
900 C will deposit Cu
`=63.5/(2 xx 96500) xx 900 = 0.296` g