If a current of 1.5 ampere flows through a metallic wire for 3 hours, then how many electrons would flow through the wire?

Explanation

`Q = I x t = 0.5 xx 2 xx 60 xx 60 = 3600` C
If = 96500 C is equivalent to flow of 1 mole of electrons `=6.023 xx 10^(23)` electrons
`=(6.02 xx 10^(23))/96500 xx 3600 = 2.246 xx 10^(22)` electrons