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Consider the following four electrodes: ...

Consider the following four electrodes:
`A=Cu^(2+)(0.0001M)//Cu_((s))`
`B=Cu^(2+)(0.1M)//Cu_((s))`
`C= Cu^(2+)(0.01M)//Cu_((s))`
`D=Cu^(2+)(0.001M)//Cu_((s))`
If the standard reduction potential of `Cu^(+2)//Cu` is `+0.34V`, the reduction potentials (in volts) of the above electrodes follow the order

A

`A gt D gt C gt B`

B

`B gt C gt D gt A`

C

`C gt D gt B gt A`

D

`A gt B gt C gt D`

Text Solution

Verified by Experts

The correct Answer is:
B
For Metal electrode `E = E^(@) + 0.059/n log [Cu^(+2)]`
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