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On electrolysing K(2)SO(4) solution usin...

On electrolysing `K_(2)SO_(4)` solution using inert electrodes, `1.68L(STP)` of gases was obtained. How many moles of `MnO_(4)^(-)` could be reduced to `Mn^(2+)` by the same quantity of electricity?

A

0.02

B

0.15

C

0.2

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
A
Volume of `H_(2)` liberated cathode `=1.68 xx 2/3`
=1.12 L
For 22.4 L of hydrogen 2F are required.
For 1.12 L of hydrogen 0.1 F are required `MnO_(4)^(-) + 5e^(-) to Mn^(2+)`
5F of electricity reduces 1 moles of `MnO_(4)^(-)`
`therefore 0.1 F` of electricity reduces 0.02 moles of `MnO_(4)^(-)`
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