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The oxidation potential of 0.05 MH(2)SO(...

The oxidation potential of `0.05 MH_(2)SO_(4)` is

A

`-2 xx 0.0591`

B

`-0.01 xx 0.0591`

C

`-2.321 xx 0.00591`

D

`+1 xx 0.0591`

Text Solution

Verified by Experts

The correct Answer is:
D
`N = M xx "Basicity" = 0.05 xx 2 =0.1`
`E = 0 + (0.059)/1 log (10^(-1)) = -0.059`
Oxidational potential `=+0.059`v.
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