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E(Zn^(2+)//Zn)^(0)=-0.76V The EMF of the...

`E_(Zn^(2+)//Zn)^(0)=-0.76V` The EMF of the cell `Zn//Zn_((1M))^(2+)"||"HCl(pH=2)|H_("(2(1 atm)"),Pt` is

A

0.878 V

B

0.642 V

C

`-0.878` V

D

`0.701` V

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(cell) = E^(0) - (0.059)/2 log 1/(10^(-2))^(2) = +0.642V`
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