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Given that E(H(2)O|H(2)|Pt) =0 at 298K. ...

Given that `E_(H_(2)O|H_(2)|Pt)` =0 at 298K. The pressure of `H_(2)` gas would be

A

`10^(-7)` atm

B

`10^(-14)` atm

C

`10^(-10)` atm

D

`10^(-12)` atm

Text Solution

Verified by Experts

The correct Answer is:
B
`E = (-RT)/F ln (PH_(2))^(1/2)/[H^(+)]` when E = 0, then,
`P_(H_(2))^(1/2) = [H^(+)] = 10^(-7) P_(H_(2)) = 10^(-14) "atm"`
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