The potential of the cell containing two hydrogen electrodes as represented below Pt, `H_(2(g))|H^(+)(10^(-6)M)"||"H^(+)(10^(-4)M)|H_(2(g)),Pt` at 298 K is

Options

A. `-0.118` V
B. `-0.0591` V
C. 0.118 V
D. `0.0591`

Answer

C

Explanation

`Ecell = E^(0) cell - (0.059)/n log ["Product"]/["Reactant"],`
`E_("cell")^(0) = 0`