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The resistance of 0.5 N solution of an e...

The resistance of `0.5` N solution of an electroolyte in a conductivity cell was found to be 45 ohms. If the electrodes in the cell are `2.2` cm apart and have an area of `3.8cm^(2)` then the equivalent conductance (in `Scm^(2)eq^(-1)`) of a solution is

A

25.73

B

15.75

C

30.75

D

35.75

Text Solution

Verified by Experts

The correct Answer is:
A
`Lambda_(eq) = (k xx 1000)/N k = 1/R xx l/a`
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