Home
Class 12
CHEMISTRY
At 25^(@)C, the ionic mobility of CH(3)C...

At `25^(@)C`, the ionic mobility of `CH_(3)COO^(-)`, `H^(+)` are respectively `4.1xx10^(-4),3.63xx10^(-3)`cm/sec. The conductivity of `0.01"M CH"_(3)COOH` is `5xx10^(-5)" S.cm"^(-1)`. Dissociation constant of `CH_(3)COOH` is

A

`1.34 xx 10^(-4)`

B

`3 xx 10^(-4)`

C

`3 xx 10^(-5)`

D

`3 xx 10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
A

`K_(alpha) = Calpha^(2) , `
`alpha = lambda_(c)/lambda_(infty) , lambda_(infty) = F(mu_(c)^(0) + mu_(a)^(0))`
Promotional Banner

Similar Questions

Explore conceptually related problems

The dissociation constant of 0.01 M CH_(3)COOH is 1.2xx10^(-5) then calculate the dissociation constant of its conjugate baze (CH_(3)COO^(-))

The degree of dissociation of 0.1N CH_(3)COOH is (K_(a)= 1xx10^(-5))

Degree of dissociation of 0.1 N CH_(3)COOH is ( Dissociation constant =1xx 10^(-5))

Calculate pH solution: 0.1 M CH_(3)COOH (K_a=1.8 xx 10^(-5))

The dissociation constant of 0.01 M CH_3COOH "is" 1.8 xx 10^(-5) , then calculate the dissociation constant of its conjugate base (CH_3COO^-)

The dissociation constatn of 0.01 M CH_(3)COOH is 1.8xx10^(-5) then calculate CH_(3)COO^(-) concentration of 0.1 M HCl solution.

Calculate pH solution: 10^(-8)M CH_(3)COOH (K_(a)=1.8 xx 10^(-5))

The equivalent conductivity of 0.1 N CH_(3) COOH " at " 25^(@)C is 80 and at infinite dilution 400 ohm^(-1) . The degree of dissociation of CH_(3)COOH is: