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Given: (i) Cu^(2+)+2e^(-) rarr Cu, E^(...

Given:
(i) `Cu^(2+)+2e^(-) rarr Cu, E^(@) = 0.337 V`
(ii) `Cu^(2+)+e^(-) rarr Cu^(+), E^(@) = 0.153 V`
Electrode potential, `E^(@)` for the reaction, `Cu^(+)+e^(-) rarr Cu`, will be

A

0.38 V

B

0.52 V

C

0.92 V

D

0.30 V

Text Solution

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The correct Answer is:
B
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