A lead storage battery containing `5.0` L of 1N `H_(2)SO_(4)` solution is operated for `9.65xx10^(5)` s with a steady current of 100 mA. Assuming volume of the solution remaining constant, normality of `H_(2)SO_(4)` will

Options

A. Remains unchanged
B. Increases by 0.20
C. Increase by unity
D. Decrease by 0.40

Answer

D

Explanation

The reaction indicates that 2 moles of `H_(2)SO_(4)` corresponds to `2 xx 96500` C and 2 mol `H_(2)SO_(4)` 4 equiv. of `H_(2)SO_(4),2 xx 96500` C consumed 4 equiv. of `H_(2)SO_(4)` and `100 xx 10^(-3) xx 9.65 xx 10^(3)` C
Consumed `=(4 xx 100 xx 10^(-3) xx 9.65 xx 10^(5))/(2 xx 96500) = 2` equiv. `H_(2)SO_(4)`
`therefore` Decrease in normality `=2/5 = 0.40`