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The specific conductance and equivalent ...

The specific conductance and equivalent conductance of a saturated solution of `BaSO_(4)` are `8xx10^(-5)ohm^(-1)cm^(-1)` and 8000 `ohm^(-1)cm^(2)"equi"^(-1)` respectively. Hence `K_(sp)` of `BaSO_(4)` is

A

`2.5 xx 10^(-10) M^(2)`

B

`2.5 xx 10^(-11) M^(2)`

C

`2.5 xx 10^(-20) M^(2)`

D

`2.5 xx 10^(-23) M^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Lambda_(eq) =(k xx 1000)/N N = (K xx 1000)/Lambda_(eq)`
Solubility = Molarity `=("Normality")/("Charge of iron")`
`BaSO_(4) to Ba^(+2) + SO^(-2)`
`K_(sp) =x^(x).y^(y).(s)^(x+y) = 1^(4).1^(s)^(1+1) =s^(2)`
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