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For the reaction R rarr P when concentra...

For the reaction `R rarr P` when concentration of R is made double the rate of reaction becomes `2.828` times the order of reaction is

A

Zero

B

1

C

`1/2`

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
`r = K[A]^(n) - (1), 2r = K[4A]^(n) - (2)`
From eq(1) & (2), we get n = 1/2
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