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In the reaction A + B rArr "Products", i...

In the reaction `A + B rArr "Products"`, if B is taken in excess, then it is an example of

A

Second order reaction

B

Zero order reaction

C

Fractional order reaction

D

First order reaction

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To determine the order of the reaction \( A + B \rightarrow \text{Products} \) when B is taken in excess, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Reaction**: The reaction involves two reactants, A and B, combining to form products. The stoichiometry of the reaction is 1:1. 2. **Writing the Rate Law**: The general form of the rate law for this reaction can be expressed as: \[ \text{Rate} = k[A]^m[B]^n \] where \( k \) is the rate constant, and \( m \) and \( n \) are the orders of the reaction with respect to A and B, respectively. 3. **Determining the Order**: Since the stoichiometry of A and B is 1:1, we initially assume that \( m = 1 \) and \( n = 1 \). Therefore, the overall order of the reaction would be: \[ \text{Overall Order} = m + n = 1 + 1 = 2 \] This indicates that the reaction is second order under normal conditions. 4. **Considering B in Excess**: When B is in excess, its concentration remains relatively constant during the reaction. This means that changes in the concentration of B will not significantly affect the rate of the reaction. 5. **Revising the Rate Law**: When B is in excess, we can simplify the rate law. The concentration of B can be treated as a constant, leading to a modified rate law: \[ \text{Rate} = k'[A] \] where \( k' = k[B]^n \) (with \( n \) being constant). 6. **Determining the New Order**: With B treated as a constant, the rate law now depends only on the concentration of A. This means the reaction behaves as a first-order reaction with respect to A: \[ \text{Overall Order} = 1 \] 7. **Conclusion**: Therefore, when B is taken in excess, the reaction \( A + B \rightarrow \text{Products} \) behaves as a first-order reaction with respect to A. ### Final Answer: The reaction \( A + B \rightarrow \text{Products} \) with B taken in excess is an example of a **first-order reaction**. ---

To determine the order of the reaction \( A + B \rightarrow \text{Products} \) when B is taken in excess, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Reaction**: The reaction involves two reactants, A and B, combining to form products. The stoichiometry of the reaction is 1:1. 2. **Writing the Rate Law**: The general form of the rate law for this reaction can be expressed as: \[ ...
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