Home
Class 12
CHEMISTRY
The rate of a certain reaction at differ...

The rate of a certain reaction at different times is as follows
`{:("Time",0,10,20,30),("Rate",3.2 xx 10^(-2), 3.18 xx 10^(-2), 3.22 xx 10^(-2), 3.19 xx 10^(-2)):}`
The order of the reaction is

A

1

B

zero

C

2

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of the reaction based on the provided rate data at different times, we can follow these steps: ### Step 1: Organize the Data First, we will organize the given data into a more readable format: | Time (s) | Rate (mol/L/s) | |----------|----------------------| | 0 | 3.2 x 10^(-2) | | 10 | 3.18 x 10^(-2) | | 20 | 3.22 x 10^(-2) | | 30 | 3.19 x 10^(-2) | ### Step 2: Analyze the Rate Values Next, we will analyze the rate values. The rates at different times are: - At time 0: 3.2 x 10^(-2) - At time 10: 3.18 x 10^(-2) - At time 20: 3.22 x 10^(-2) - At time 30: 3.19 x 10^(-2) We can see that the rates are very close to each other, indicating that they are nearly constant. ### Step 3: Determine the Relationship Between Rate and Concentration For a zero-order reaction, the rate of reaction is independent of the concentration of the reactants. This means that even as time progresses and the concentration of the reactants decreases, the rate remains constant. ### Step 4: Conclusion Since the rate does not change significantly with time and remains approximately constant, we can conclude that the reaction is a **zero-order reaction**. ### Final Answer The order of the reaction is **zero**. ---

To determine the order of the reaction based on the provided rate data at different times, we can follow these steps: ### Step 1: Organize the Data First, we will organize the given data into a more readable format: | Time (s) | Rate (mol/L/s) | |----------|----------------------| | 0 | 3.2 x 10^(-2) | ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    NARAYNA|Exercise EXERCISE -1 (C.W) (MOLECULARITY)|5 Videos
  • CHEMICAL KINETICS

    NARAYNA|Exercise EXERCISE -1 (C.W) (HALF-LIFE)|7 Videos
  • CHEMICAL KINETICS

    NARAYNA|Exercise EXERCISE -1 (C.W) (RATE OF REACTION & FACTORS)|14 Videos
  • CARBOXYLIC ACID

    NARAYNA|Exercise All Questions|288 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    NARAYNA|Exercise ASSERTION & REASON TYPE QUESTIONS|10 Videos

Similar Questions

Explore conceptually related problems

The rates of a certain at differnet time intervals are as follows : {:("Time (seconds)",0,10,20),("Rate",1.8xx10^(-2),1.82xx10^(-2),1.79xx10^(-2)"mol" L^(-1)s^(-1)):} The reactio is of :

The rates of a certain reaction (d c//d t) at different times are as follows {:("Time",,, Rate("mole litre"^(-1)sec^(-1)),),(0,,,2.8 xx 10^(-2),),(10,,,2.78xx10^(-2),),(20,,,2.81xx10^(-2),),(30,,,2.79xx10^(-2),):} The reaction is

3 xx 10^(5) + 4 xx 10^(3) + 7 xx 10^(2) + 5 is equal to

The rate constant of a reaction is 3.25 xx 10^(-3) " mol"^(-2) L^(2) " min"^(-1) . The order of raction is

For a reaction aA +b B rarr products the following data were found {:(,[A],[B],"rate",),(,0.10,0.10,1xx10^(-2),),(,0.20,0.20,8xx10^(-2),),(,0.10,0.20,2xx10^(-2),):} The overall order of reaction is

(2.4xx10^(3))-:(8xx10^(-2))=?3xx10^(-5)b3xx10^(4)c.3xx10^(5)d.30