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A rarr B, k(A)=10^(15) e^(-2000//T) C ...

`A rarr B, k_(A)=10^(15) e^(-2000//T)`
`C rarr D, k_(c)=10^(14) e^(-1000//T)`
Temperature at which `k_(A)=k_(c)` is

A

1000 K

B

2000 K

C

`2000/2.303`K

D

`1000/2.303` K

Text Solution

Verified by Experts

The correct Answer is:
D
`10^(15).e^(-2000//T) = 10^(14).e^(-1000//T)`
`10=e^(1000//T)`
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