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The hydrogenation of vegetable ghee at 2...

The hydrogenation of vegetable ghee at `25^(@)C` reduces the pressure of `H_(2)` form `2 atm` to `1.2 atm` in `50min`. Calculate the rate of reaction in terms of change of
(a) Pressure per minute
(b) Molarity per second

A

`1.09 xx 10^(-6)`

B

`1.09 xx 10^(-5)`

C

`1.09 xx 10^(-7)`

D

`1.09 xx 10^(-8)`

Text Solution

Verified by Experts

The correct Answer is:
B
P=0.8 atm / 50 min
`PV = nRT , P=n/V RT, M =P/(RT)`
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NARAYNA-CHEMICAL KINETICS -EXERCISE -2 (H.W) (RATE OF REACTION & FACTORS)
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