The time for half-life period of a certain reaction, `A rarr` products is `1 h`. When the initial concentration of the reactant `'A'` is `2.0 "mol" L^(-1)`, how much time does it take for its concentration to come from `0.50` to `0.25 "mol" L^(-1)`, if it is zero order reaction ?

Options

A. 1
B. 2
C. 3
D. 0

Answer

B

Explanation

`T_(1)/T_(2) =(a_(2)/a_(1))^(n-1) , 50/25 (1.0/0.5)^(n-1), 2=(2)^(n-1)` or `2^(1) = (2)^(n-1)`
`therefore 1=n-1`. Hence, n=1+2=2. Reaction is of second order.