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Rate constant has the unit "mol"^(-2)L^(...

Rate constant has the unit `"mol"^(-2)L^(-2)s^(-1)` , then order of reaction is

A

zero order, t= 7.5 sec

B

first

C

second

D

third

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The correct Answer is:
To determine the order of a reaction given that the rate constant has the unit of \( \text{mol}^{-2} \text{L}^2 \text{s}^{-1} \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between rate, rate constant, and concentration**: The rate of a reaction can be expressed as: \[ \text{Rate} = k \times [A]^n \] where \( k \) is the rate constant, \( [A] \) is the concentration of the reactant, and \( n \) is the order of the reaction. 2. **Identify the units of rate**: The unit of rate is typically expressed as concentration per time. In SI units, this can be written as: \[ \text{Rate} = \frac{\text{mol}}{\text{L} \cdot \text{s}} \] 3. **Express the unit of the rate constant \( k \)**: Given that the unit of \( k \) is \( \text{mol}^{-2} \text{L}^2 \text{s}^{-1} \), we can express this in terms of the concentration unit: \[ k = \text{mol}^{-2} \text{L}^2 \text{s}^{-1} \] 4. **Relate the units of \( k \) to the order of the reaction**: From the equation of the rate, we can rearrange it to find the units of \( k \): \[ k = \frac{\text{Rate}}{[A]^n} \] Substituting the units: \[ k = \frac{\frac{\text{mol}}{\text{L} \cdot \text{s}}}{\left(\frac{\text{mol}}{\text{L}}\right)^n} \] This simplifies to: \[ k = \frac{\frac{\text{mol}}{\text{L} \cdot \text{s}}}{\frac{\text{mol}^n}{\text{L}^n}} = \frac{\text{mol}^{1-n}}{\text{L}^{1-n} \cdot \text{s}} \] 5. **Set the units equal**: Now we can set the units of \( k \) equal to the given units: \[ \frac{\text{mol}^{1-n}}{\text{L}^{1-n} \cdot \text{s}} = \text{mol}^{-2} \text{L}^2 \text{s}^{-1} \] 6. **Compare the exponents**: From the left side: - For \( \text{mol} \): \( 1 - n = -2 \) → \( n = 3 \) - For \( \text{L} \): \( -(1-n) = 2 \) → \( n - 1 = -2 \) → \( n = 3 \) - For \( \text{s} \): \( -1 = -1 \) (this is consistent) 7. **Conclusion**: The order of the reaction is \( n = 3 \). ### Final Answer: The order of the reaction is **3**.

To determine the order of a reaction given that the rate constant has the unit of \( \text{mol}^{-2} \text{L}^2 \text{s}^{-1} \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between rate, rate constant, and concentration**: The rate of a reaction can be expressed as: \[ \text{Rate} = k \times [A]^n ...
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