3.6 gram of oxygen of adsorbed on 1.2 g of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 273 K ?

Options

A. `0.19 Lg^(-1)`
B. `1 Lg^(-1)`
C. `2.1 Lg^(-1)`
D. `3.2 Lg^(-1)`

Answer

C

Explanation

3.6 gm of `O_(2)` is adsobed per 1.2 gms of adsorbent mass of `O_(2)` adsorbed per gram of adsorbent = ? =`(3.6)/(1.2) =3`
No of moles `O_(2)` per gram adsorbent `=(3)/(32)`
1 mole of `O_(2) rarr 22.4` lists at STP
`(3)/(32)` moles `O_(2)` ? = 2.10