1.30 `cm^(3)` of `N_(2)` gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is 0.16 `nm^(2)`. What is the surface area per gram of silica gel ?
`(N_(A)=6.023xx10^(23))`

Options

A. `1.6 m^(2) g^(-1)`
B. `5.568 m^(2)g^(-1)`
C. `3.48m^(2)g^(-1)`
D. `4.42 m^(2)g^(-1)`

Answer

B

Explanation

Number of `N_(2)` molecules adsorbed per rgam of silica gel =` ((6.023xx10^(23)xx1.30))/(22400) = 3.48 xx10^(19)`
Area of cross section of `N_(2)` molecule
`=0.16 nm^(2)= 1.6xx10^(-19) m^(2)`
`:.` Surface area covered per gram of silica gel
`=1.6xx10^(-19)xx3.48xx10^(19)=5.568 m^(2)`