Graph between `log x//m` and `log p` is a straight line inclined at an angle of `45^@` . When pressure is `0.5 atm` and `1n k = 0.693`, the amount of solute adsorbed per gram of adsorbent will be:

Options

A. 1g/g adsorbent
B. 1.5 g/g adsorbent
C. 2.5 g/g adsorbent
D. 0.25 g/g adsorbent

Answer

C

Explanation

`"log" (x)/(m) = (1)/(n)` log p +log k, n=1