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The coagulation of 200 mL of a positive ...

The coagulation of `200 mL` of a positive colloid took place when `0.73 g HCl` was added to it without changing the volume much. The flocculation value of `HCl` for the colloid is
a. `36.5` , b. `100` , c. `200` , d. `150`

A

0.365

B

`36.5`

C

100

D

150

Text Solution

Verified by Experts

The correct Answer is:
C
Number of milli moles of HCL = `(0.73 xx1000)/(36.5) =20`
Flocculation value of HCL =`(20)/(0.2L)-=100` milli moles per litre
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