Ethyledene bromide is

Options

A. `CH_3CH_2Br`
B. `BrCH_2CH_2Br`
C. `CH_3CHBr_2`
D. `CH_2=CHBr`

Explanation

To determine the formula of ethylidene bromide, we need to understand the structure of the compound. Ethylidene bromide is a vicinal dihalide, which means it has two halogen atoms (in this case, bromine) attached to adjacent carbon atoms. Let's break down the steps to arrive at the correct formula.

### Step-by-Step Solution:

1. **Identify the Base Structure**:
- Ethylidene refers to a structure derived from ethylene (C2H4). The base structure consists of two carbon atoms connected by a double bond.

2. **Add Bromine Atoms**:
- Since it is a vicinal dihalide, we need to add two bromine (Br) atoms to the adjacent carbon atoms.

3. **Construct the Molecular Formula**:
- The structure can be represented as follows:
- The first carbon (C1) will have two hydrogen (H) atoms and one bromine (Br) atom.
- The second carbon (C2) will also have two hydrogen (H) atoms and one bromine (Br) atom.
- Therefore, the molecular formula can be written as:
- C1: CH2Br
- C2: CH2Br

4. **Combine the Atoms**:
- Combining the atoms from both carbon atoms, we get the overall molecular formula:
- C2H4Br2

5. **Final Formula**:
- The final formula of ethylidene bromide is C2H4Br2.

### Final Answer:
The formula of ethylidene bromide is **C2H4Br2**.