`CHCl_3` on oxidation by air in presence of light gives

Options

A. phosgene
B. formic acid
C. chloropicrin
D. `"CCl"_4`

Explanation

To solve the question regarding the oxidation of chloroform (CHCl₃) in the presence of air and light, we can follow these steps:

### Step 1: Identify the Reactants
The reactant in this case is chloroform, which has the chemical formula CHCl₃.

### Step 2: Understand the Reaction Conditions
The reaction is taking place under oxidation conditions, which means that the chloroform will lose hydrogen and gain oxygen. The presence of air (which contains oxygen) and light (which can provide energy for the reaction) is crucial for this oxidation process.

### Step 3: Determine the Oxidation Process
During the oxidation of chloroform, the hydrogen atom attached to the carbon atom will be replaced by a hydroxyl group (–OH). This is a common transformation in organic chemistry where a hydrogen atom is replaced by an oxygen-containing group.

### Step 4: Write the Reaction
The oxidation of chloroform (CHCl₃) can be represented as:
\[ \text{CHCl}_3 + \text{O}_2 \xrightarrow{\text{light}} \text{COCl}_2 + \text{HCl} \]
Here, chloroform is oxidized to phosgene (COCl₂) and hydrochloric acid (HCl).

### Step 5: Identify the Product
The primary product of this reaction is phosgene (COCl₂), which is a toxic gas. The reaction also produces hydrochloric acid (HCl) as a byproduct.

### Final Answer
When CHCl₃ is oxidized by air in the presence of light, it produces phosgene (COCl₂) and hydrochloric acid (HCl).

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