The reaction `C_6H_5I+2Na+CH_3Ioverset(dry ether) rarrC_6H_5CH_3+2NaI` is

Options

A. Wurtz reaction
B. Fitting reaction
C. Wurts - Fitting reaction
D. Sandmeyer reaction

Explanation

To solve the question regarding the reaction \( C_6H_5I + 2Na + CH_3I \overset{dry \ ether}{\rightarrow} C_6H_5CH_3 + 2NaI \), we need to identify the name of this reaction.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the reaction are phenyl iodide (\( C_6H_5I \)) and methyl iodide (\( CH_3I \)), along with sodium (\( Na \)) in the presence of dry ether.

2. **Understand the Reaction Type**:
This reaction involves the coupling of two alkyl halides (one aryl halide and one alkyl halide) in the presence of sodium. The sodium acts as a reducing agent, facilitating the formation of a new carbon-carbon bond.

3. **Recognize the Mechanism**:
The reaction mechanism involves the formation of a new bond between the phenyl group and the methyl group, resulting in toluene (\( C_6H_5CH_3 \)) and sodium iodide (\( NaI \)) as products.

4. **Identify the Name of the Reaction**:
This reaction is known as the **Wurtz-Fittig reaction**. The Wurtz reaction typically involves the coupling of alkyl halides, while the Fittig reaction specifically refers to the coupling of aryl halides. Since we are dealing with an aryl halide and an alkyl halide, this reaction is a combination of both concepts.

5. **Write the Final Answer**:
Therefore, the name of the reaction \( C_6H_5I + 2Na + CH_3I \overset{dry \ ether}{\rightarrow} C_6H_5CH_3 + 2NaI \) is the **Wurtz-Fittig reaction**.

### Final Answer:
The reaction is a **Wurtz-Fittig reaction**.