The reaction `C_2H_5ONa+BrC_2H_5rarrC_2H_5-O-C_2H_5+NaBr` is called

Options

A. Frankland reaction
B. Wurtz reaction
C. Williamson's synthesis
D. Cannizaro reaction

Explanation

To solve the question regarding the reaction \( \text{C}_2\text{H}_5\text{ONa} + \text{BrC}_2\text{H}_5 \rightarrow \text{C}_2\text{H}_5\text{-O-C}_2\text{H}_5 + \text{NaBr} \), we need to analyze the components and the type of reaction taking place.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The first reactant is sodium ethoxide (\( \text{C}_2\text{H}_5\text{ONa} \)), which is a strong nucleophile.
- The second reactant is bromoethane (\( \text{BrC}_2\text{H}_5 \)), which contains a good leaving group (bromine).

2. **Understand the Mechanism**:
- Sodium ethoxide acts as a nucleophile and attacks the electrophilic carbon atom in bromoethane. This carbon is electrophilic due to the presence of the bromine atom, which is a good leaving group.
- The nucleophilic attack leads to the formation of an ether.

3. **Formation of the Product**:
- The product formed is diethyl ether (\( \text{C}_2\text{H}_5\text{-O-C}_2\text{H}_5 \)) and sodium bromide (\( \text{NaBr} \)).
- This reaction is a classic example of ether synthesis.

4. **Name the Reaction**:
- The reaction is known as **Williamson Ether Synthesis**. This is a method for synthesizing ethers by the reaction of an alkoxide ion with a primary alkyl halide.

### Final Answer:
The reaction \( \text{C}_2\text{H}_5\text{ONa} + \text{BrC}_2\text{H}_5 \rightarrow \text{C}_2\text{H}_5\text{-O-C}_2\text{H}_5 + \text{NaBr} \) is called **Williamson Ether Synthesis**.

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