During Friedel craft reaction of Benzene with `CH_3Cl` in presence of `AlCl_3` find product is

Options

A.
B.
C.
D.

Explanation

To solve the question regarding the product formed during the Friedel-Crafts reaction of benzene with CH₃Cl in the presence of AlCl₃, we can follow these steps:

### Step 1: Understand the Reaction Type
The Friedel-Crafts reaction is an electrophilic aromatic substitution (EAS) reaction. In this reaction, benzene acts as a nucleophile and reacts with an electrophile.

**Hint:** Remember that benzene is electron-rich due to its delocalized π electrons, making it susceptible to attack by electrophiles.

### Step 2: Identify the Electrophile
In this reaction, CH₃Cl (methyl chloride) is used. In the presence of AlCl₃ (aluminum chloride), which is a Lewis acid, CH₃Cl can generate a methyl cation (CH₃⁺) as the electrophile.

**Hint:** A Lewis acid like AlCl₃ can accept electron pairs, facilitating the formation of the electrophile.

### Step 3: Formation of the Methyl Cation
When CH₃Cl reacts with AlCl₃, the bond between carbon and chlorine breaks. The chlorine atom takes the bonding electrons, forming a methyl cation (CH₃⁺) and AlCl₄⁻.

**Hint:** The more electronegative chlorine pulls the electrons towards itself, leaving a positively charged carbon.

### Step 4: Electrophilic Attack on Benzene
The methyl cation (CH₃⁺) acts as the electrophile and attacks the electron-rich benzene ring. This results in the formation of a new carbon-carbon bond, leading to the formation of a carbocation intermediate.

**Hint:** The π bond of benzene breaks to form a new bond with the electrophile, creating a temporary positive charge on the benzene ring.

### Step 5: Deprotonation to Form the Final Product
To stabilize the carbocation, a hydrogen atom from the benzene ring is removed (deprotonation), resulting in the formation of toluene (C₆H₅CH₃). The hydrogen combines with the AlCl₄⁻ to form HCl and regenerate AlCl₃.

**Hint:** The removal of a proton restores aromaticity to the benzene ring and completes the substitution reaction.

### Step 6: Write the Final Products
The final products of the reaction are toluene (C₆H₅CH₃) and hydrogen chloride (HCl). The AlCl₃ is regenerated and acts as a catalyst.

**Hint:** Catalysts are not consumed in the reaction; they are regenerated at the end.

### Conclusion
The product formed during the Friedel-Crafts reaction of benzene with CH₃Cl in the presence of AlCl₃ is toluene (C₆H₅CH₃) and HCl.

**Final Answer:** Toluene and HCl.