`C_2H_5Cl +Ag OH rarrA+AgCl` .
`A+CH_3COClrarrA+AgCl.` ''C '' is

Options

A. Ethyl acetate
B. Methyl acetate
C. Butanon - 2
D. Propanone

Explanation

To solve the given question, we will analyze the reactions step by step.

### Step 1: Identify the Reaction
The first reaction is:
\[ C_2H_5Cl + AgOH \rightarrow A + AgCl \]

Here, \( C_2H_5Cl \) (ethyl chloride) reacts with silver hydroxide (\( AgOH \)). Silver chloride (\( AgCl \)) is formed as a precipitate, and we need to identify compound \( A \).

### Step 2: Determine Compound A
In this reaction, silver hydroxide acts as a nucleophile and replaces the chlorine atom in ethyl chloride. The product \( A \) is ethyl alcohol (\( C_2H_5OH \)).

So, we have:
\[ A = C_2H_5OH \]

### Step 3: Second Reaction
Now, we look at the second reaction:
\[ A + CH_3COCl \rightarrow A + AgCl \]

Here, \( A \) (which we found to be \( C_2H_5OH \)) reacts with acetyl chloride (\( CH_3COCl \)).

### Step 4: Mechanism of the Reaction
In this reaction, the hydroxyl group (\( -OH \)) of ethyl alcohol attacks the carbonyl carbon of acetyl chloride. This leads to the formation of an intermediate where the \( -OH \) group is bonded to the carbonyl carbon, and the chlorine leaves as \( AgCl \).

### Step 5: Final Product
After the formation of the intermediate, the oxygen of the hydroxyl group will lose a proton, resulting in the formation of an ester. The final product will be ethyl acetate:
\[ C_2H_5OCOCH_3 \]

### Step 6: Identify Compound C
Thus, compound \( C \) is ethyl acetate, which can be represented as:
\[ C = CH_3COOC_2H_5 \]

### Conclusion
The final answer is:
**C is ethyl acetate.**

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