In the reaction `CH_3-overset(CH_3)overset(|)(CH)-CH(OH)-CH_2-CH_3 +HIoverset("Heated")rarr` compound will be formed ?

Options

A. `CH_3-overset(CH_3)overset(|)(CH)-CH_3OH+CH_3-CH_2-I`
B. `CH_3-overset(CH_3)overset(|)(CH)-CH_3-I+CH_3CH_2OH`
C. `CH_3-underset(CH_3)underset(|)(CH)-CH_3+CH_3CH_2OH`
D. `CH_3-underset(CH_3)underset(|)(CH)-CH_2OH+CH_3CH_2`

Explanation

To solve the reaction of the compound \( CH_3-CH(CH_3)-CH(OH)-CH_2-CH_3 \) with HI when heated, we will follow these steps:

### Step 1: Identify the Reactants
The reactant is \( CH_3-CH(CH_3)-CH(OH)-CH_2-CH_3 \) and it will react with hydroiodic acid (HI).

### Step 2: Protonation of the Alcohol
When HI is added, the hydroxyl group (-OH) will be protonated by the \( H^+ \) from HI. This leads to the formation of water (H2O) and a carbocation. The reaction can be represented as:
\[ CH_3-CH(CH_3)-CH(OH)-CH_2-CH_3 + H^+ \rightarrow CH_3-CH(CH_3)-C^+(H_2O)-CH_2-CH_3 \]

### Step 3: Formation of Carbocation
The protonation of the -OH group leads to the formation of a better leaving group (water). The resulting carbocation will be:
\[ CH_3-CH(CH_3)-C^+-CH_2-CH_3 \]

### Step 4: Carbocation Rearrangement
Next, we check the stability of the carbocation. The carbocation can rearrange to form a more stable carbocation by shifting a hydride ion (H-) from the adjacent carbon:
\[ CH_3-CH^+(CH_3)-CH_2-CH_3 \rightarrow CH_3-CH_2-CH^+(CH_3)-CH_3 \]

### Step 5: Nucleophilic Attack by Iodide Ion
The iodide ion (\( I^- \)) from HI will now act as a nucleophile and attack the carbocation, leading to the formation of the final product:
\[ CH_3-CH_2-CH(CH_3)-CH_3 + I^- \rightarrow CH_3-CH_2-CH(I)-CH_3 \]

### Step 6: Final Product
The final product formed from the reaction is:
\[ CH_3-CH_2-CH(I)-CH_3 \]
This compound is 1-iodobutane.

### Summary of Reaction
The overall reaction can be summarized as:
\[ CH_3-CH(CH_3)-CH(OH)-CH_2-CH_3 + HI \xrightarrow{\text{Heated}} CH_3-CH_2-CH(I)-CH_3 + H_2O \]

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