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MnF(7) is not stable while Mn(2)O(7) is ...

`MnF_(7)` is not stable while `Mn_(2)O_(7)` is stable.

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Incorrect statement about Mn_(2)O_(7) is :

Mn_2O_7 is a basic oxide.

Assertion : The highest manganese fluroide is MnF_(4) and the highest oxide is Mn_(2) O_(7) . Reason : In Mn_(2) O_(7) , each Mn is tetrahedrally surrounded by O's including Mn-O-Mn bridge.

2Mn_(2)O_(7)rarr4MnO_(2)+3O_(2) ( if M is m ol.wt. of Mn_(2)O_(7) ). Find the equivalent weight of Mn_(2)O_(7) in above change.

(a) Give reasons for the following : (i) Mn^(3+) is a good oxidising agent. (ii) E(M^(2+)//M)^(@) values are not regular for first row transition metals (3d series). (iii) Although 'F' is more electronegative then 'O', the highest Mn fluoride is MnF_(4) whereas the highest oxide is Mn_(2)O_(7) . Complete the following equations : (ii) 2 CrO_(4)^(2-)+2H^(+)rarr (ii) KMnO_(4)overset("heat")rarr