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Zn^(+2) dissolves in excess of NaOH due ...

`Zn^(+2)` dissolves in excess of NaOH due to the formation of

A

Soluble Zn `(OH)_(2)`

B

Soluble `Na_(2) (Zn(OH)_(4)]`

C

Soluble Na `[Zn(OH)_(3)]`

D

ZnO

Text Solution

Verified by Experts

The correct Answer is:
B
`Zn^(+2)+2NaOH to Na_(2)ZnO_(2) +H_(2)`
`Na_(2)ZnO_(2)+2H_(2)O to Na_(2) [Zn(OH)_(4)]`
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NARAYNA-CO-ORDINATE COMPOUNDS -Exercise -1 (C.W.)
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