Hexaquotitanium (II) Chloride represented as

Options

A. `[Ti(H_(2)O)_(6)]Cl_(3)`
B. `[TiCl_(3)] 6H_(2)O`
C. `[Ti(H_(2)O)_(5)Cl]Cl_(2)`
D. `[Ti(H_(2)O)_(3)Cl_(3)]`

Answer

To represent Hexaqua Titanium (II) Chloride, we need to follow these steps:

### Step 1: Identify the Components
Hexaqua Titanium (II) Chloride consists of:
- Titanium (Ti) in a +2 oxidation state.
- Six water molecules (H2O) acting as ligands.
- Two chloride ions (Cl-) as counter ions.

### Step 2: Determine the Coordination Sphere
The term "hexa" indicates that there are six water molecules coordinated to the titanium ion. Since water is a neutral ligand, it does not contribute any charge to the coordination sphere. Therefore, the charge of the coordination sphere is solely determined by the titanium ion.

### Step 3: Calculate the Overall Charge
- The oxidation state of titanium is +2.
- The oxidation state of water (H2O) is 0 because it is a neutral ligand.

Thus, the overall charge of the coordination sphere is:
\[ \text{Charge of Ti} + \text{Charge of H2O} = +2 + 0 = +2 \]

### Step 4: Determine the Counter Ions
To balance the +2 charge of the coordination sphere, we need two chloride ions (Cl-), each contributing a -1 charge. Therefore, we need:
\[ 2 \times (-1) = -2 \]

### Step 5: Write the Final Formula
Combining the coordination sphere and the counter ions, we can write the formula for Hexaqua Titanium (II) Chloride as:
\[ \text{[Ti(H2O)6]}^{2+} \text{Cl}_2^{-} \]

Thus, the complete representation is:
\[ \text{Ti(H2O)6Cl2} \]

### Final Answer:
The structure of Hexaqua Titanium (II) Chloride is represented as:
\[ \text{Ti(H2O)6Cl2} \]

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