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What is (are) number (s) of unpaired ele...

What is (are) number (s) of unpaired electron(s) in the square planar `[Pt(CN)_4]^(2-)` ion ?

A

Zero

B

1

C

4

D

6

Text Solution

Verified by Experts

The correct Answer is:
A
Outer electronic configuration of Pt is `5d^(9) 6s^(1)`. Outer electronic configuration of `Pt^(2+)" is "5d^(8)`
As `CN^(-)` is strong field ligand, so paring will take place.
`Pt^(2+)`
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