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When CH(2)=CH -CO OH is reduced with LiA...

When `CH_(2)=CH -CO OH` is reduced with `LiAlH_(4)` the compound obtained will be

A

`CH_(3) - CH_(2)` - COOH

B

`CH_(2)` = CH -`CH_(2)` OH

C

`CH_(3)-CH_(2) - CH_(2)`OH

D

`CH_(3) -CH_(2)` - CHO

Text Solution

Verified by Experts

`"LiAlH"_(4)` reduces - COOH to `- CH_(2)` OH without affecting C = C bond.
`CH_(2) = CH - "COOH" + 4H underset(-H_(2)O)overset("LiAlH"_(4))(rarr) CH_(2) = CH - CH_(2)`OH
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