`CH_(3)C equiv N underset(HCl)overset(SnCl_(2))(rarr) CH_(3) CH = NH overset(H_(2)O)(rarr) `X. Find out X.

Options

A. `C_(2) H_(5)`OH
B. `C_(2) H_(5)` CHO
C. `CH_(3)`CHO
D. `C_(6)H_(5)`CHO

Answer

To solve the problem, we need to follow the reaction steps provided in the question. Let's break it down step by step.

### Step 1: Identify the starting compound
The starting compound is CH₃C≡N (propanenitrile) which is treated with HCl and SnCl₂. The reaction involves the conversion of the nitrile group (C≡N) to an imine (C=N).

### Step 2: Reaction with HCl and SnCl₂
When CH₃C≡N is treated with HCl and SnCl₂, the nitrile undergoes hydrolysis. The SnCl₂ acts as a reducing agent, facilitating the conversion of the nitrile to an imine. The imine formed is CH₃CH=NH.

### Step 3: Hydrolysis of the imine
Next, the imine (CH₃CH=NH) reacts with water (H₂O). The nitrogen in the imine has a lone pair of electrons that can act as a nucleophile. It will attack the electrophilic carbon of the imine, leading to the formation of a new compound.

### Step 4: Formation of the final product
During the hydrolysis, the imine will convert into an aldehyde. The reaction will yield CH₃CHO (acetaldehyde) as the final product after the elimination of ammonia (NH₃).

### Conclusion
Thus, the compound X formed from the given reaction is **acetaldehyde (CH₃CHO)**.

### Final Answer
**X = CH₃CHO (Acetaldehyde)**

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