I` overset(O_(2))(larr)"Benzaldehyde" overset(NH_(3))(rarr)`II, I, II are -

Options

A. Benzoic acid, Benzaldehyde ammonia
B. Benzoic acid, Hydrobenzamide
C. Phenyl acetic , Benzaldehyde ammoina
D. Benozic acid, Aniline

Answer

To solve the question, we need to analyze the reactions involving benzaldehyde, oxygen, and ammonia. Here’s a step-by-step breakdown of the process:

### Step 1: Identify the reaction of benzaldehyde with oxygen.
Benzaldehyde (C₇H₆O) can be oxidized in the presence of oxygen (O₂). The oxidation of benzaldehyde leads to the formation of benzoic acid (C₇H₆O₂).

**Hint:** Remember that aldehydes are generally oxidized to carboxylic acids.

### Step 2: Write the reaction for the oxidation of benzaldehyde.
The balanced reaction for the oxidation of benzaldehyde can be represented as:
\[ \text{Benzaldehyde} + \text{O}_2 \rightarrow \text{Benzoic Acid} \]

Thus, we can conclude that:
- **I = Benzoic Acid**

**Hint:** Look for the functional group changes when an aldehyde is oxidized.

### Step 3: Identify the reaction of benzaldehyde with ammonia.
When benzaldehyde reacts with ammonia (NH₃), it forms an imine. The reaction involves the nucleophilic attack of the lone pair of electrons from ammonia on the carbonyl carbon of benzaldehyde.

**Hint:** Recall that imines are formed when aldehydes or ketones react with primary amines.

### Step 4: Write the reaction for the formation of the imine.
The reaction can be represented as:
\[ \text{Benzaldehyde} + \text{NH}_3 \rightarrow \text{Hydrobenzamide} \]
In this reaction, the hydroxyl group (OH) is eliminated, leading to the formation of a C=N bond.

Thus, we can conclude that:
- **II = Hydrobenzamide**

**Hint:** Consider the stability of the product formed; imines can often polymerize or further react.

### Final Conclusion:
Based on the reactions analyzed:
- **I = Benzoic Acid**
- **II = Hydrobenzamide**

### Summary:
The final answers to the question are:
- I = Benzoic Acid
- II = Hydrobenzamide