Product (P) obtained in the reaction given below CO + NaOH`rarr` (P)

Options

A. HCOONa
B. `C_(2)H_(2)O_(4)`
C. HCOOH
D. `CH_(3)`COOH

Explanation

To determine the product (P) obtained from the reaction of carbon monoxide (CO) with sodium hydroxide (NaOH), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in the given reaction are carbon monoxide (CO) and sodium hydroxide (NaOH).

2. **Understand the Reaction Conditions**: The reaction is typically carried out under high temperature and high pressure. The common conditions for this reaction are around 120 to 130 degrees Celsius.

3. **Determine the Nature of Reactants**:
- Carbon monoxide (CO) is a neutral molecule.
- Sodium hydroxide (NaOH) is a strong base.

4. **Reaction Mechanism**: Under the specified conditions, CO reacts with NaOH. The base (NaOH) facilitates the formation of a carboxylate ion from carbon monoxide.

5. **Formation of Sodium Formate**: The product formed from this reaction is sodium formate (HCOONa). The reaction can be represented as:
\[ CO + NaOH \rightarrow HCOONa \]
Here, the carbon monoxide is converted into the formate ion (HCOO-) which pairs with sodium (Na+) to form sodium formate.

6. **Identify the Product**: The product (P) of the reaction is sodium formate (HCOONa).

7. **Select the Correct Option**: From the options provided (HCOO-Na, C2H2O4, HCOOH, NCS3, COOH), the correct answer is HCOO-Na, which corresponds to sodium formate.

### Final Answer:
The product (P) obtained from the reaction of CO with NaOH is sodium formate (HCOONa).

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