In the presence of iodine catalyst, chlorine reacts with acetic acid to form

Options

A. `CH_(3) - overset(O)overset(||)(C ) - Cl`
B. `C//CH_(2) - overset(O)overset(||)(C ) - OH`
C. `CH_(3) - underset(Cl)underset(|)overset(Cl)overset(|)(C ) - OH`
D. `CH_(3) - overset(O)overset(||) (C ) - O - Cl`

Explanation

To solve the problem of what products are formed when chlorine reacts with acetic acid in the presence of an iodine catalyst, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Conditions**:
- The reactants are chlorine (Cl2) and acetic acid (CH3COOH).
- The reaction is conducted in the presence of iodine (I2) as a catalyst.

2. **Understand the Reaction Type**:
- This reaction involves alpha halogenation, where chlorine substitutes a hydrogen atom at the alpha position (the carbon adjacent to the carboxylic acid group) of acetic acid.

3. **Mechanism of the Reaction**:
- The carbonyl group (C=O) of acetic acid is involved in the reaction. The mechanism can be summarized as follows:
- The C=O bond in acetic acid interacts with the iodine catalyst, leading to the formation of a more reactive intermediate.
- The chlorine molecule (Cl2) then attacks the alpha carbon (the carbon next to the carboxylic acid group), resulting in the substitution of a hydrogen atom with a chlorine atom.

4. **Formation of Products**:
- The primary product formed from this reaction is chloroacetic acid (ClCH2COOH).
- Additionally, iodine monochloride (ICl) is formed as a byproduct due to the involvement of iodine in the reaction.

5. **Final Product**:
- The final product of the reaction is chloroacetic acid (ClCH2COOH), and the byproduct is iodine monochloride (ICl).

### Conclusion:
In the presence of iodine catalyst, chlorine reacts with acetic acid to form chloroacetic acid (ClCH2COOH) and iodine monochloride (ICl).

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