In the reaction sequence :
`C_(6)H_(5) CHO overset("HCN")(rarr) [X] overset(H_(2)O // H^(oplus))(rarr)`product
Product will be :

Options

A. Optically inactive acid
B. Optically active `alpha` - hydroxy acid
C. Racemic mixture of two optically in active primary alcohols
D. Racemic mixture of two optically active primary alcohols

Explanation

To solve the given problem, we will analyze the reaction sequence step by step.

### Step 1: Identify the initial compound
The starting compound is **C₆H₅CHO**, which is benzaldehyde. It consists of a benzene ring (C₆H₅) attached to a formyl group (CHO).

### Step 2: Reaction with HCN
When benzaldehyde reacts with hydrogen cyanide (HCN), it undergoes a nucleophilic addition reaction. The cyanide ion (CN⁻) attacks the carbonyl carbon of the aldehyde, leading to the formation of a cyanohydrin.

**Reaction:**
\[ \text{C}_6\text{H}_5\text{CHO} + \text{HCN} \rightarrow \text{C}_6\text{H}_5\text{C(OH)(CN)} \]

Here, the product formed is a cyanohydrin, which has a hydroxyl group (OH) and a cyanide group (CN) attached to the same carbon.

### Step 3: Hydrolysis of the cyanohydrin
The next step involves the hydrolysis of the cyanohydrin in the presence of water (H₂O) and an acid (H⁺). During hydrolysis, the cyanide group (CN) is converted into a carboxylic acid (COOH).

**Reaction:**
\[ \text{C}_6\text{H}_5\text{C(OH)(CN)} + \text{H}_2\text{O} \xrightarrow{\text{H}^+} \text{C}_6\text{H}_5\text{COOH} + \text{NH}_4\text{OH} \]

The final product is **benzoic acid (C₆H₅COOH)**.

### Final Answer
The product formed after the complete reaction sequence is **benzoic acid (C₆H₅COOH)**.

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