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In the given reaction : Carbonyl compoun...

In the given reaction : Carbonyl compound,
`C_(8) H_(16) O [X] overset("KMnO"_(4)//H^(oplus)//Delta)(rarr) ` 2 moles of butanoic acid [X] will be :

A

2-octanone

B

3-octanone

C

4-octanone

D

2-methyl-3-heptanone

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the carbonyl compound \( C_8H_{16}O \) that, upon oxidation, yields two moles of butanoic acid. Let's break down the steps: ### Step 1: Understand the Reaction The reaction involves the oxidation of a carbonyl compound (which can be either an aldehyde or a ketone) to produce butanoic acid. Butanoic acid has the formula \( C_4H_8O_2 \). ### Step 2: Determine the Number of Carbons The carbonyl compound has 8 carbons (C8) and the product (butanoic acid) has 4 carbons. Since we are producing 2 moles of butanoic acid, the total number of carbons in the products is \( 2 \times 4 = 8 \). This means that the carbonyl compound must be split into two parts that each contribute to the formation of butanoic acid. ### Step 3: Identify the Type of Carbonyl Compound Since we are getting two moles of butanoic acid, the carbonyl compound must be a ketone. This is because: - Aldehydes would retain the same number of carbons upon oxidation. - Ketones can break down into smaller carbon chains. ### Step 4: Analyze the Given Options We have the following options for \( C_8H_{16}O \): 1. 2-octanone 2. 3-octanone 3. 4-octanone 4. 2-methylheptanone ### Step 5: Consider the Symmetry of the Ketone To yield two identical butanoic acid molecules, the ketone must be symmetrical. This means that the carbonyl group should be positioned such that upon oxidation, it can break down evenly into two parts. ### Step 6: Evaluate Each Option - **2-octanone**: The carbonyl group is at the second carbon. Oxidation would not yield two identical butanoic acids. - **3-octanone**: The carbonyl group is at the third carbon. This would also not yield two identical butanoic acids. - **4-octanone**: The carbonyl group is at the fourth carbon. Upon oxidation, this can break down into two butanoic acids. - **2-methylheptanone**: This is not symmetrical and would not yield two identical butanoic acids. ### Step 7: Conclusion The only option that allows for the symmetrical breakdown into two moles of butanoic acid is **4-octanone**. Thus, the carbonyl compound \( C_8H_{16}O \) is **4-octanone**. ### Final Answer: The carbonyl compound \( C_8H_{16}O \) that yields two moles of butanoic acid upon oxidation is **4-octanone**. ---

To solve the problem, we need to identify the carbonyl compound \( C_8H_{16}O \) that, upon oxidation, yields two moles of butanoic acid. Let's break down the steps: ### Step 1: Understand the Reaction The reaction involves the oxidation of a carbonyl compound (which can be either an aldehyde or a ketone) to produce butanoic acid. Butanoic acid has the formula \( C_4H_8O_2 \). ### Step 2: Determine the Number of Carbons The carbonyl compound has 8 carbons (C8) and the product (butanoic acid) has 4 carbons. Since we are producing 2 moles of butanoic acid, the total number of carbons in the products is \( 2 \times 4 = 8 \). This means that the carbonyl compound must be split into two parts that each contribute to the formation of butanoic acid. ...
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NARAYNA-ALDEHYDES, KETONES & CARBOXYLIC ACIDS-EXERCISE -II (C.W.)
  1. In the given reaction : CH(3)-overset(OH)overset(|)CH-underset(CH(3)...

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  2. In the reaction sequence : C(6)H(5) CHO overset("HCN")(rarr) [X] ove...

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  3. In the given reaction : Carbonyl compound, C(8) H(16) O [X] overset...

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  4. In the reaction X + Y underset(5^(@)C)overset(NaOH)(rarr) CH(3)-ov...

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  5. In the reaction : [X] will be :

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  6. In the given reaction CH(3)-CH(2)-COOHunderset((ii)." "Br(2)//Delta)ov...

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  7. In the given reaction :

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  8. In the given reaction CH(3)-COOH underset(underset("(iii) "H(2)O //H^(...

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  9. In the given reactions :

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  10. The reduction of benzoyl chloride with H(2)//Pd-BaSO(4) produces

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  11. Which reaction can produce R - CO-Ar species :

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  12. Which one is a mixed ketone :

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  13. Hydrolysis of an ester gives a carboxylic acid which on Kolbe's electr...

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  14. Reaction of aniline with acety1 chloride in the presence of NaOH gives...

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  15. m-chlorobenzaldehyde on reaction with conc. KOH at room temperature gi...

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  16. In Etard's reaction toluene is oxidised to benzaldehyde using

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  17. Which of the following does not give brick red ppt. with Fehling solut...

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  18. The organic product formed in the reaction C(6) H(5)"COOCH"(3) under...

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  19. The class of compounds that are reduced to primary alcohols and also r...

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  20. Benzoic acid with "SOCl"(2) to give

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