Identify X,
`H_(3)C - overset(CH_(3))overset(|)(C ) = O underset("dry ether")overset(CH_(3)"Mgl")(rarr) A overset(H_(2)O)(rarr)`X,

Options

A. `CH_(3)OH`
B. `CH_(3)CH_(2)`OH
C. `CH_(3)"CHOHCH"_(3)`
D. `CH_(3)"C(OH)"(CH_(3))_(2)`

Explanation

To solve the problem, we need to identify the compound X formed from the reaction of a ketone with a Grignard reagent followed by hydrolysis. Let's break it down step by step.

### Step 1: Identify the starting compound
We start with a ketone represented as:
\[ \text{H}_3\text{C} - \text{C}(=O) - \text{C}(\text{CH}_3) \]
This ketone has two methyl groups (CH₃) attached to the carbonyl carbon.

### Step 2: Reaction with Grignard reagent
The Grignard reagent given is:
\[ \text{CH}_3\text{MgI} \]
In this reaction, the nucleophilic carbon from the Grignard reagent (CH₃⁻) will attack the electrophilic carbonyl carbon of the ketone.

The reaction can be represented as:
\[ \text{H}_3\text{C} - \text{C}(=O) - \text{C}(\text{CH}_3) + \text{CH}_3\text{MgI} \rightarrow \text{A} \]

### Step 3: Formation of the intermediate (A)
When the nucleophile attacks, the carbonyl group (C=O) will be converted into an alcohol group (C-OH), and we will have:
\[ \text{A} = \text{H}_3\text{C} - \text{C}(\text{OH}) - \text{C}(\text{CH}_3)(\text{CH}_3) \]
This means that the intermediate A will have a tertiary alcohol structure.

### Step 4: Hydrolysis of the intermediate
Now, we perform hydrolysis on compound A. Hydrolysis involves the addition of water, which will convert the magnesium alkoxide into a hydroxyl group:
\[ \text{A} + \text{H}_2\text{O} \rightarrow \text{X} \]

### Step 5: Identify the final product (X)
After hydrolysis, the final product X will be:
\[ \text{X} = \text{H}_3\text{C} - \text{C}(\text{OH}) - \text{C}(\text{CH}_3)(\text{CH}_3) \]
This compound is a tertiary alcohol with the structure:
\[ \text{X} = \text{2-methyl-2-butanol} \]

### Final Answer
Thus, the compound X is 2-methyl-2-butanol.

---