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Action of benzoic acid with hydroazoic a...

Action of benzoic acid with hydroazoic acid in presence of conc. `H_(2)SO_(4)` followed by hydrolysis:

A

Aniline

B

Benzamide

C

Phenyl cyanide

D

All

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To solve the problem of the action of benzoic acid with hydroazoic acid in the presence of concentrated sulfuric acid followed by hydrolysis, we can break it down into a series of steps: ### Step 1: Reactants and Initial Setup We start with benzoic acid (C₆H₅COOH) and hydroazoic acid (HN₃) in the presence of concentrated sulfuric acid (H₂SO₄). The sulfuric acid acts as a catalyst and protonates the benzoic acid, making it more reactive. **Hint:** Identify the reactants and their roles in the reaction. ### Step 2: Protonation of Benzoic Acid The lone pair of electrons on the oxygen atom of the carboxylic acid group in benzoic acid attacks a proton (H⁺) from sulfuric acid, resulting in the formation of a positively charged benzoic acid derivative. **Hint:** Look for the role of sulfuric acid in protonating the reactants. ### Step 3: Formation of a Reactive Intermediate The protonated benzoic acid undergoes intramolecular proton transfer, which leads to the formation of a good leaving group (water) and a positively charged carbonyl compound. **Hint:** Consider how intramolecular proton transfer can stabilize the intermediate. ### Step 4: Nucleophilic Attack by Hydroazoic Acid The negatively charged nitrogen from hydroazoic acid (N₃⁻) attacks the carbonyl carbon of the reactive intermediate, forming a new compound that contains a nitrogen group. **Hint:** Focus on the nucleophilic nature of hydroazoic acid and its attack on the carbonyl carbon. ### Step 5: Rearrangement and Loss of Nitrogen Gas The newly formed compound undergoes rearrangement, resulting in the loss of nitrogen gas (N₂) and the formation of an intermediate that is positively charged. **Hint:** Identify the significance of nitrogen gas leaving the reaction. ### Step 6: Hydrolysis Water (from hydrolysis) attacks the positively charged carbon, leading to the formation of an amine and a carboxylic acid. The carboxylic acid can then deprotonate to yield the final product. **Hint:** Recognize the role of water in hydrolysis and how it contributes to the final product. ### Step 7: Final Product The final product of this reaction is aniline (C₆H₅NH₂) along with carbon dioxide (CO₂) as a byproduct. **Hint:** Determine the final product by considering the structure of the reactants and the transformations that occurred. ### Conclusion The overall reaction can be summarized as: \[ \text{C}_6\text{H}_5\text{COOH} + \text{HN}_3 \xrightarrow{\text{H}_2\text{SO}_4} \text{C}_6\text{H}_5\text{NH}_2 + \text{CO}_2 \] Thus, the product of the action of benzoic acid with hydroazoic acid in the presence of concentrated sulfuric acid followed by hydrolysis is **aniline**.

To solve the problem of the action of benzoic acid with hydroazoic acid in the presence of concentrated sulfuric acid followed by hydrolysis, we can break it down into a series of steps: ### Step 1: Reactants and Initial Setup We start with benzoic acid (C₆H₅COOH) and hydroazoic acid (HN₃) in the presence of concentrated sulfuric acid (H₂SO₄). The sulfuric acid acts as a catalyst and protonates the benzoic acid, making it more reactive. **Hint:** Identify the reactants and their roles in the reaction. ### Step 2: Protonation of Benzoic Acid ...
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NARAYNA-ALDEHYDES, KETONES & CARBOXYLIC ACIDS-EXERCISE -II (H.W.)
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  5. Which of the following has the maximum acidic strength?

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  8. The general formula of both aldehyde & ketone is

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  16. The reverse of esterification process is called:

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  18. Explain the reactivity of acyl compounds in the order:

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  19. Acetic anhydride on readuction with LiAlH"(4) in ether gives :

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