`2CH_(3) "CHO" overset(Al(OC_(2)H_(5))_(3))(rarr) CH_(3) "COOCH"_(2)CH_(3)`
this reactions is called :

Options

A. Cannizzaro's reaction
B. Aldol condensation
C. Claisen's reaction
D. Tischenko reaction

Answer

To solve the question regarding the reaction of two molecules of acetaldehyde with triethoxyaluminium to form ethyl acetate, we can break it down step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are two molecules of acetaldehyde (CH₃CHO) and triethoxyaluminium (Al(OC₂H₅)₃).

**Hint**: Look for the functional groups in the reactants to understand their reactivity.

2. **Understand the Reaction Type**:
The reaction involves the formation of a new carbon-carbon bond and the conversion of aldehydes into esters. This suggests that it may be a condensation reaction.

**Hint**: Consider the types of reactions that involve aldehydes and esters.

3. **Mechanism Overview**:
- The aluminum in triethoxyaluminium has a vacant d-orbital and is electrophilic, which allows it to interact with the oxygen of the acetaldehyde.
- The oxygen from acetaldehyde attacks the aluminum, forming a complex.
- The second molecule of acetaldehyde then attacks this complex, leading to the formation of a new carbon-carbon bond.

**Hint**: Focus on how the electrophilic and nucleophilic sites interact in the mechanism.

4. **Formation of Ethyl Acetate**:
- Through a series of steps involving bond rearrangements and the transfer of hydrogen, the final product formed is ethyl acetate (CH₃COOCH₂CH₃).
- The reaction essentially converts the aldehyde into an ester.

**Hint**: Keep track of the atoms and bonds during the reaction to see how the product is formed.

5. **Naming the Reaction**:
- This specific reaction is known as the **T-Schenkow reaction**, which is characterized by the conversion of aldehydes into esters using aluminum alkoxides.

**Hint**: Recall the names of reactions involving aldehydes and esters to identify the correct one.

### Final Answer:
The reaction is called the **T-Schenkow reaction**.